4x=100+x^2

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Solution for 4x=100+x^2 equation: 



4x=100+x^2

We move all terms to the left:

4x-(100+x^2)=0

We get rid of parentheses

-x^2+4x-100=0

We add all the numbers together, and all the variables

-1x^2+4x-100=0

a = -1; b = 4; c = -100;
Δ = b2-4ac
Δ = 42-4·(-1)·(-100)
Δ = -384
Delta is less than zero, so there is no solution for the equation

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